document.write( "Question 347150: Facts:
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document.write( "Random sample of 44
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document.write( "Standard deviation of 2.4
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document.write( "Point estimate of 7.59\r
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document.write( "Obtain an approximate 95.44% confidence interval for the mean number of young.
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document.write( "This is my response 2*2.4=4.8 x-4.8 = 7.59-4.8 = 2.79 x+4.8=7.59+4.8=12.39, so 95.44% certain between 2.79 and 12.39.
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document.write( "Can you please tell me if I have done this correct. Thank you for all of your help.
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Algebra.Com's Answer #248279 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Facts: \n" ); document.write( "Random sample of 44 \n" ); document.write( "Standard deviation of 2.4 \n" ); document.write( "Point estimate of 7.59 \n" ); document.write( "Obtain an approximate 95.44% confidence interval for the mean number of young. \n" ); document.write( "------------- \n" ); document.write( "1.00-0.9544 = \n" ); document.write( "x-bar: 7.59 \n" ); document.write( "E = [-invT(0.0228,43]*2.4/sqrt(44) = 0.7449 \n" ); document.write( "-------- \n" ); document.write( "95.44% CI: 7.59-0.7449 < u < 7.59+0.7449 \n" ); document.write( "--- \n" ); document.write( "95.44% CI: 6.8451 < u < 8.3349 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================================== \n" ); document.write( " |