document.write( "Question 347150: Facts:
\n" ); document.write( "Random sample of 44
\n" ); document.write( "Standard deviation of 2.4
\n" ); document.write( "Point estimate of 7.59\r
\n" ); document.write( "\n" ); document.write( "Obtain an approximate 95.44% confidence interval for the mean number of young.
\n" ); document.write( "This is my response 2*2.4=4.8 x-4.8 = 7.59-4.8 = 2.79 x+4.8=7.59+4.8=12.39, so 95.44% certain between 2.79 and 12.39.
\n" ); document.write( "Can you please tell me if I have done this correct. Thank you for all of your help.
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Algebra.Com's Answer #248279 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Facts:
\n" ); document.write( "Random sample of 44
\n" ); document.write( "Standard deviation of 2.4
\n" ); document.write( "Point estimate of 7.59
\n" ); document.write( "Obtain an approximate 95.44% confidence interval for the mean number of young.
\n" ); document.write( "-------------
\n" ); document.write( "1.00-0.9544 =
\n" ); document.write( "x-bar: 7.59
\n" ); document.write( "E = [-invT(0.0228,43]*2.4/sqrt(44) = 0.7449
\n" ); document.write( "--------
\n" ); document.write( "95.44% CI: 7.59-0.7449 < u < 7.59+0.7449
\n" ); document.write( "---
\n" ); document.write( "95.44% CI: 6.8451 < u < 8.3349
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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