document.write( "Question 346956: A person is biking 8m/s when the bike passes a car. The car starts from rest and accelerates at 3m/s. How long will it take for the car to catch up with the bike. \n" ); document.write( "

Algebra.Com's Answer #248220 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
A person is biking 8m/s when the bike passes a car.
\n" ); document.write( " The car starts from rest and accelerates at 3m/s.
\n" ); document.write( " How long will it take for the car to catch up with the bike.
\n" ); document.write( ":
\n" ); document.write( "Let t = time for the car to overtake the bike
\n" ); document.write( "(this also is the time that the car accelerates at 3 m/sec
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, both will travel the same distance, dist = speed * time
\n" ); document.write( ":
\n" ); document.write( " $\"%28%280+%2B+3t%29%29%2F2\"$ * t = 8t
\n" ); document.write( "Multiply both sides by 2, results:
\n" ); document.write( "3t * t = 16t
\n" ); document.write( ":
\n" ); document.write( "3t^2 = 16
\n" ); document.write( "Divide both sides by t
\n" ); document.write( "3t = 16
\n" ); document.write( "t = $\"16%2F3\"$
\n" ); document.write( "t = 5 $\"1%2F3\"$ seconds for the car to catch the bike
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check this;
\n" ); document.write( "Car will accelerate to: 3*5.33 = 16 m/sec
\n" ); document.write( "From a standing stop, it's average speed will be half, 8 m/sec
\n" ); document.write( "Both will travel 8m/sec for 5.33 min or about 42.7 meters \n" ); document.write( "

\n" );