document.write( "Question 39343This question is from textbook INTERMEDIATE ALGEBRA
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Algebra.Com's Answer #24821 by AnlytcPhil(1806)\"\" \"About 
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SOLVE THE INEQUALITY. COLLECT\r\n" );
document.write( "THE XS ON THE LEFT SIDE. WRITE THE SOLUTION SET IN \r\n" );
document.write( "INTERVAL NOTATION:\r\n" );
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document.write( "(4/3)(X + 1) < (1/2)(X - 3)\r\n" );
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document.write( "First clear of fractions by multiplying through by \r\n" );
document.write( "the LCD of 6:\r\n" );
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document.write( "Start by placing brackets around each side:\r\n" );
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document.write( "     [(4/3)(X + 1)] < [(1/2)(X - 3)]\r\n" );
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document.write( "Put \"6·\" in front of each \r\n" );
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document.write( "   6·[(4/3)(X + 1)] < 6·[(1/2)(X - 3)]\r\n" );
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document.write( "Use the associative law to switch the brackets:\r\n" );
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document.write( "   [6·(4/3)](X + 1) < [6·(1/2)](X - 3)\r\n" );
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document.write( "          [8](X + 1) < [3](X - 3)\r\n" );
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document.write( "             8X + 8 < 3X - 9\r\n" );
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document.write( "                 5X < -17\r\n" );
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document.write( "                  X < -17/5\r\n" );
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document.write( "Note: in that last step we DO NOT reverse the sign of\r\n" );
document.write( "inequality because we divided through by a positive\r\n" );
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document.write( "Now we graph the inequality on a number line:\r\n" );
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document.write( "-oo   <==================)-----------------  oo\r\n" );
document.write( "                      -17/5\r\n" );
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document.write( "Interval notation  (-oo, -17/5)\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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