document.write( "Question 347107: In 2002, capitol city had a population of 2010, and Shelbyville had a population of 1040. if capitol city grows at a rate of 150 people a year and Shelbyville grows at a rate of 340 people a year , when will the population of Shelbyville be greater than that of capitol city ? \n" ); document.write( "
Algebra.Com's Answer #248202 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In 2002, capitol city had a population of 2010, and Shelbyville had a population of 1040. if capitol city grows at a rate of 150 people a year and Shelbyville grows at a rate of 340 people a year , when will the population of Shelbyville be greater than that of capitol city ?
\n" ); document.write( "-----
\n" ); document.write( "Capitol Equation: C(x) = 150x+2010
\n" ); document.write( "---
\n" ); document.write( "Shelby Equation: S(x) = 340x + 1040
\n" ); document.write( "-----------
\n" ); document.write( "Question When will S(x)>C(x)
\n" ); document.write( "---
\n" ); document.write( "340x+1040 > 150x+2010
\n" ); document.write( "---
\n" ); document.write( "190x > 970
\n" ); document.write( "x > 5.1053 years
\n" ); document.write( "---
\n" ); document.write( "Year: 2002 = 5.1053 = 2007.153
\n" ); document.write( "Rounding up Year = 2008
\n" ); document.write( "====================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );