document.write( "Question 347107: In 2002, capitol city had a population of 2010, and Shelbyville had a population of 1040. if capitol city grows at a rate of 150 people a year and Shelbyville grows at a rate of 340 people a year , when will the population of Shelbyville be greater than that of capitol city ? \n" ); document.write( "
Algebra.Com's Answer #248202 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 2002, capitol city had a population of 2010, and Shelbyville had a population of 1040. if capitol city grows at a rate of 150 people a year and Shelbyville grows at a rate of 340 people a year , when will the population of Shelbyville be greater than that of capitol city ? \n" ); document.write( "----- \n" ); document.write( "Capitol Equation: C(x) = 150x+2010 \n" ); document.write( "--- \n" ); document.write( "Shelby Equation: S(x) = 340x + 1040 \n" ); document.write( "----------- \n" ); document.write( "Question When will S(x)>C(x) \n" ); document.write( "--- \n" ); document.write( "340x+1040 > 150x+2010 \n" ); document.write( "--- \n" ); document.write( "190x > 970 \n" ); document.write( "x > 5.1053 years \n" ); document.write( "--- \n" ); document.write( "Year: 2002 = 5.1053 = 2007.153 \n" ); document.write( "Rounding up Year = 2008 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |