document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346358>Question 346358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> e^x=3^x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248187 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you mean e^x = 3^(x+2) [ e^x = 3^x + 2 has no solutions, <BR>\n" );
document.write( "because e^x < 3^x for all x... ]<BR>\n" );
document.write( "take ln of left and right side\r<BR>\n" );
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document.write( "x = (x+2) ln(3)<BR>\n" );
document.write( "x ( 1 - ln(3) ) = 2 ln(3)<BR>\n" );
document.write( "x = 2 ln(3) /(1- ln(3) )<BR>\n" );
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