document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346142>Question 346142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A portion of a wall is a right triangle with a height that is 3 feet more than its base. If the area of the triangle is 27 square feet, find the base </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248185 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of Triangle = 1/2 Base X Height\r<BR>\n" );
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document.write( "=> Let Y = the Base<BR>\n" );
document.write( "=> Then Height = Y + 3\r<BR>\n" );
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document.write( "=> 27 = 1/2 { Y * ( Y + 3) }<BR>\n" );
document.write( "=> 27 = 1/2 { Y^2 + 3Y }<BR>\n" );
document.write( "=> 54 = Y^2 + 3Y (Both side multiple by 2 to eliminate the faction)<BR>\n" );
document.write( "=> 0 = Y^2 + 3Y - 54<BR>\n" );
document.write( "=> 0 = (Y+9)(Y-6)<BR>\n" );
document.write( "=> Y = -9 or +6<BR>\n" );
document.write( "=> Since the absolute value of Y has to be more than 0 in order for the Triangle to be real<BR>\n" );
document.write( "=> Y = +6<BR>\n" );
document.write( "=> In Co-ordinate Trigonometry, the + and - sign will mean the direction/co-odination of the triangle<BR>\n" );
document.write( "=> Then both -9 and +6 can be the answer for the base.\r<BR>\n" );
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document.write( "Answer: Base is 6 feet, Height is 9 feet.<BR>\n" );
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