document.write( "Question 39325: 1. f(x)= x^+3x-4 divide over x^+5x-6\r
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document.write( "find va vertical asymptote
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document.write( " ha horizontal asymptote
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document.write( " x-intercept
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document.write( " y=intercept
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document.write( " and graph it w the t chart plz help me solve this problem thank you
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Algebra.Com's Answer #24818 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, we are to avoid x+6=0, which is when x=-6. This the vertical asymptote.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now for the horizontal one: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, we are to avoid y-1=0, which is when y=1. this is the horizontal asymptote.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, plot the axes and draw the 2 dotted asymptotes. We need a couple of points to anchor the 2 halves of the plot.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, when x=0, we have y=4/6 --> y=2/3 \n" ); document.write( "and when y=0, we have x=4/(-1) --> x=-4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plot these 2 points and draw a curve in the quadrant joining these points and heading towards the asymptotes. Then draw a matching curve in the diagonally opposite quadrant of your graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want to, pick some random value of x, say x=-5 and find y. It should be a small-ish negative y-value, since the curve crosses the x-axis at x=-4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |