document.write( "Question 39348: Please help again, appreciate any and all help.
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document.write( "2) Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following:
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document.write( "a) What is r, the ratio between 2 consecutive terms? \r
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document.write( "Show work in this space. \r
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document.write( "b) Using the formula for the nth term of a geometric sequence, what is the 10th term?
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document.write( "Answer: the sum of the first 10 terms is: Show work in this space. \r
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document.write( "c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms?
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document.write( "Answer: Show work in this space
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Algebra.Com's Answer #24816 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! Common ratio...the number you multiple a term by to generate the next term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1*3 is 3 \n" ); document.write( "3*3 is 9 \n" ); document.write( "9*3 is 27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--> r is 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b. \n" ); document.write( "1st term of a GP = a \n" ); document.write( "2nd term of a GP = ar \n" ); document.write( "3rd term of a GP = \n" ); document.write( "nth term of a GP = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, 10th term is \n" ); document.write( " \n" ); document.write( "19683\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c. Sum of n terms = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "29524\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |