document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347072>Question 347072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if you have 67 beads twice as many white beads as red beads and twice as many green beads as white beads and the number of blue beads is only one more than the number of green beads.  How many beads of each color do you have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248159 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you have 67 beads twice as many white beads as red beads and twice as many green beads as white beads and the number of blue beads is only one more than the number of green beads.  How many beads of each color do you have?\r<BR>\n" );
document.write( "\n" );
document.write( "white  be 2x<BR>\n" );
document.write( "red will be x<BR>\n" );
document.write( "green 4x<BR>\n" );
document.write( "blue1+4x<BR>\n" );
document.write( "total 67\r<BR>\n" );
document.write( "\n" );
document.write( "2x+x+4x+1+4x=67<BR>\n" );
document.write( "11x+1=67<BR>\n" );
document.write( "11x=66<BR>\n" );
document.write( "x= 6<BR>\n" );
document.write( "you can work out the others<BR>\n" );
document.write( "white= 12<BR>\n" );
document.write( "green 24<BR>\n" );
document.write( "bkue= 25<BR>\n" );
document.write( "Total 67 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );