document.write( "Question 347067: a mason can build a wall in 6 hours less than an apprentive. together they can build the wall in 4 hours. how long would it take the apprentice, working alone, to build the wall? \n" ); document.write( "
Algebra.Com's Answer #248152 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes the apprentice working alone to build the wall \n" ); document.write( "Then the apprentice works at the rate of 1/x wall per hour \n" ); document.write( "And x-6=amount of time it takes the mason to build the wall \n" ); document.write( "Then the mason works at the rate of 1/(x-6) wall per hour \n" ); document.write( "Together the mason and apprentice works at the rate of 1/4 wall per hour \n" ); document.write( "So our equation to solve is: \n" ); document.write( "1/x + 1/(x-6)=1/4 multiply each term by 4x(x-6) \n" ); document.write( "4(x-6)+4x=x(x-6) get rid of parens \n" ); document.write( "4x-24+4x=x^2-6x or \n" ); document.write( "8x-24=x^2-6x subtract 8x from and add 24 to both sides \n" ); document.write( "x^2-6x-8x+24=0 \n" ); document.write( "x^2-14x+24=0 ----quadratic in standard form and it can be factored \n" ); document.write( "(x-2)(x-12)=0 \n" ); document.write( "x=2 hrs----THIS CANNOT BE A SOLUTION; THE MASON CANNOT WORK 6 HRS LESS THAN 2 HOURS ---CANNOT HAVE NEGATIVE TIMES IN THIS CASE \n" ); document.write( "x=12 hrs----time it takes apprentice working alone \n" ); document.write( "Then mason takes 6 hrs working alone to build the wall\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "1/12 + 1/6=1/4 \n" ); document.write( "3/12=1/4 \n" ); document.write( "1/4=1/4\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |