document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=347065>Question 347065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 85. The second is 7 more than the first. The third is 2 more than four times the second. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248151 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the first number<BR>\n" );
document.write( "Then x+7=second number <BR>\n" );
document.write( "And 4(x+7)+2=third number (2 more than 4 times the second)<BR>\n" );
document.write( "Now we are told that:<BR>\n" );
document.write( "x+(x+7)+(4(x+7)+2)=85 get rid of parens<BR>\n" );
document.write( "x+x+7+4x+28+2=85 simplify<BR>\n" );
document.write( "6x+37=85 subtract 37 from each side<BR>\n" );
document.write( "6x+37-37=85-37<BR>\n" );
document.write( "6x=48<BR>\n" );
document.write( "x=8---first number<BR>\n" );
document.write( "x+7=8+7=15 second number<BR>\n" );
document.write( "4(x+7)+2=4*15+2=62 third number\r<BR>\n" );
document.write( "\n" );
document.write( "CK<BR>\n" );
document.write( "8+15+62=85<BR>\n" );
document.write( "85=85\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );