document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346984>Question 346984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice the difference of a number and 8 is equal to three times the sum of the numer and 3 find the number?\r<BR>\n" );
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document.write( "x-2+8  not sure if thats correct but my text book got -25 as an answer can anyone help me with how my text book got -25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248129 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I believe this is what you are needing:\r<BR>\n" );
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document.write( "2x-x+8=3x+3\r<BR>\n" );
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document.write( "Since 2x and -x are like terms, add -x to 2x to get x.<BR>\n" );
document.write( "x+8=3x+3\r<BR>\n" );
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document.write( "Since 3x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 3x from both sides.<BR>\n" );
document.write( "x+8-3x=3\r<BR>\n" );
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document.write( "Since x and -3x are like terms, add -3x to x to get -2x.<BR>\n" );
document.write( "-2x+8=3\r<BR>\n" );
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document.write( "Since 8 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 8 from both sides.<BR>\n" );
document.write( "-2x=-8+3\r<BR>\n" );
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document.write( "Add 3 to -8 to get -5.<BR>\n" );
document.write( "-2x=-5\r<BR>\n" );
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document.write( "Divide each term in the equation by -2.<BR>\n" );
document.write( "-(2x)/(-2)=-(5)/(-2)\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "x=-(5)/(-2)\r<BR>\n" );
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document.write( "x= -25 </SPAN>\n" );
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