document.write( "Question 346961: The supplement of an angle is 36 degrees less than twice the supplement of the complement of the angle. Find the measure of the supplement. Can you also explain it too? Thank you so much \n" ); document.write( "
Algebra.Com's Answer #248103 by haileytucki(390)![]() ![]() You can put this solution on YOUR website! Ok, let me know if this helps;-) \n" ); document.write( "1. Let x=measure of the angle.\r \n" ); document.write( "\n" ); document.write( "Two angles angles are supplementary is the sum of their measures is 180 degrees. \r \n" ); document.write( "\n" ); document.write( "Two angles angles are complementary is the sum of their measures is 90 degrees. \r \n" ); document.write( "\n" ); document.write( "supplement of the angle \n" ); document.write( "= 180-x\r \n" ); document.write( "\n" ); document.write( "complement of the angle \n" ); document.write( "= 90-x\r \n" ); document.write( "\n" ); document.write( "supplement of the complement of the angle \n" ); document.write( "= 180-(90-x)=90+x\r \n" ); document.write( "\n" ); document.write( "twice the supplement of the complement of the angle \n" ); document.write( "= 2(90+x)=180+2x\r \n" ); document.write( "\n" ); document.write( "The supplement of an angle is 36 degrees less than twice the supplement of the complement of the angle \n" ); document.write( "=> (180-x) + 36 = 180+2x\r \n" ); document.write( "\n" ); document.write( "Solve for x. You should get x=12.\r \n" ); document.write( "\n" ); document.write( "Since we are looking for the supplement, then the answer is 180-x=180-12=168. \n" ); document.write( " |