document.write( "Question 346953: A bullet is fired horizontally at a target, and the sound of its impact is heard 1.5 seconds later. If the speed of the bullet is 3300 ft/sec and the speed of sound is 1100 ft/sec how far away is the target? \n" ); document.write( "
Algebra.Com's Answer #248100 by mananth(16946)\"\" \"About 
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let target distance be x
\n" ); document.write( "bullet speed = 3300ft/sec
\n" ); document.write( "sound speed = 1100 ft/sec
\n" ); document.write( "sound heard after 1.5 seconds = 3/2
\n" ); document.write( "..
\n" ); document.write( "x/3300 + x/ 1100 = 3/2
\n" ); document.write( "LCD = 3300
\n" ); document.write( "x+3x /3300 = 3/2
\n" ); document.write( "4x/3300 = 3/2
\n" ); document.write( "4x= 3*3300/2
\n" ); document.write( "4x=9900/2
\n" ); document.write( "4x= 4950
\n" ); document.write( "x= 4950/4
\n" ); document.write( "x=1237.5 feet
\n" ); document.write( "
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