document.write( "Question 346953: A bullet is fired horizontally at a target, and the sound of its impact is heard 1.5 seconds later. If the speed of the bullet is 3300 ft/sec and the speed of sound is 1100 ft/sec how far away is the target? \n" ); document.write( "
Algebra.Com's Answer #248100 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let target distance be x \n" ); document.write( "bullet speed = 3300ft/sec \n" ); document.write( "sound speed = 1100 ft/sec \n" ); document.write( "sound heard after 1.5 seconds = 3/2 \n" ); document.write( ".. \n" ); document.write( "x/3300 + x/ 1100 = 3/2 \n" ); document.write( "LCD = 3300 \n" ); document.write( "x+3x /3300 = 3/2 \n" ); document.write( "4x/3300 = 3/2 \n" ); document.write( "4x= 3*3300/2 \n" ); document.write( "4x=9900/2 \n" ); document.write( "4x= 4950 \n" ); document.write( "x= 4950/4 \n" ); document.write( "x=1237.5 feet \n" ); document.write( " |