document.write( "Question 4976: the sum of the digits of a two digit number is 9. if the digits are reversed, the new number is 63 greater than the original number. Find the original number. \n" ); document.write( "

Algebra.Com's Answer #2481 by xcentaur(357) $\"\"$ $\"About$

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let the digits be x and y
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\n" ); document.write( "x+y=9...[1]
\n" ); document.write( "x+10y=63+10x+y
\n" ); document.write( "x-10x+10y-y=63
\n" ); document.write( "9y-9x=63
\n" ); document.write( "y-x=7.....[2]
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\n" ); document.write( "y+x=9
\n" ); document.write( "y-x=7
\n" ); document.write( "addig the two eqns we get
\n" ); document.write( "2y=16
\n" ); document.write( "y=8
\n" ); document.write( "y+x=9
\n" ); document.write( "x=9-y=9-8=1
\n" ); document.write( "

\n" ); document.write( "number=10x+y=18
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