document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346279>Question 346279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a biker mixed 11 pounds of raisins that cost $2.30 per pound with peanuts that cost $4.50 per pound to make a mixture that cost $3.29 per pound. how many pounds of peanuts did the biker use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248092 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let p = amount of peanuts used by the biker\r<BR>\n" );
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document.write( "2.30(11) + 4.50p = 3.29(p + 11)\r<BR>\n" );
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document.write( "Can you finish?\r<BR>\n" );
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document.write( "All you have to do is solve for p. </SPAN>\n" );
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