document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346925>Question 346925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 9:00 on Saturday two bicyclist heading in opposite directions pass each other on a bicycle path. the bicyclist heading north is riding 6km/hr faster than the bicyclist heading south. at 10:15,they are 42.5km apart. find the two bicyclists rates. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248064 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> at 9:00 two bicyclist heading in opposite directions<BR>\n" );
document.write( "the bicyclist heading south x km/h<BR>\n" );
document.write( "bicyclist heading north x+6 km/hr. <BR>\n" );
document.write( "at 10:15,= 1 1/4 hour = 5/4 hours<BR>\n" );
document.write( "they are 42.5km apart.<BR>\n" );
document.write( ".....<BR>\n" );
document.write( "5/4 *x +5/4 *(x+6) = 42.5<BR>\n" );
document.write( "5x/4+(5x+30) /4 =42.5<BR>\n" );
document.write( "(5x+5x+30)=4*42.5<BR>\n" );
document.write( "10x+30=170<BR>\n" );
document.write( "10x=170-30<BR>\n" );
document.write( "10x=140<BR>\n" );
document.write( "x=14 km/h  south<BR>\n" );
document.write( "14 +6 = 20km/h north bound <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );