document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346905>Question 346905</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find the remaining zeros of f.\r<BR>\n" );
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document.write( "Degree 6; zeros: -2, 7, 2 - 5i, -7 + i  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248060 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For any polynomial with Real coefficients, the complex roots/zeros, if any, will always come in conjugate pairs: a + bi and a - bu<br><BR>\n" );
document.write( "So the two missing zeros are:<BR>\n" );
document.write( "1) the conjugate of 2 - 5i: 2 + 5i<BR>\n" );
document.write( "2) the conjugate of -7 + 1: -7 - i </SPAN>\n" );
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