document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346448>Question 346448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Elizabeth visits her friend Andrew and then returns home by the same route. She always walks 2km/h when going uphill, 6km/h when going downhill and 3km/h when on level ground. If her total walking time is 6 hours, then what is the total distance she walks in km?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #248026 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=248026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance / rate = time\r<BR>\n" );
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document.write( "a = distance going uphill, returning downhill<BR>\n" );
document.write( "b = distance going and returning level<BR>\n" );
document.write( "c = distance going downhill, returning uphill\r<BR>\n" );
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document.write( "a/2 + b/3 + c/6 + c/2 + b/3 + a/6 = 6\r<BR>\n" );
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document.write( "3a + 2b + c + 3c + 2b + a = 36\r<BR>\n" );
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document.write( "4(a + b + c) = 36 </SPAN>\n" );
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