document.write( "Question 4985: a two digit number is 6 times the sum of its digits. the tens digit is 1 more than the units digit. find the number. \n" ); document.write( "
Algebra.Com's Answer #2480 by xcentaur(357)\"\" \"About 
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let the digits of the number be x and y
\n" ); document.write( "then the number is (10x+y)
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\n" ); document.write( "Given the two digit number is 6 times the sum of its digits.
\n" ); document.write( "Sum of its digits = (x+y)
\n" ); document.write( "From given statement we get
\n" ); document.write( "(10x+y)=6(x+y)..................[1]
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\n" ); document.write( "Also we have,the tens digit is 1 more than the units digit.
\n" ); document.write( "this means that x=y+1...........[2]
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\n" ); document.write( "From equations one and two we get,
\n" ); document.write( "10x+y=6(x+y)
\n" ); document.write( "10x+y=6x+6y
\n" ); document.write( "10x-6x=6y-y
\n" ); document.write( "4x=5y
\n" ); document.write( "x=5y/4...........................[3]
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\n" ); document.write( "we get x=5y/4=y+1
\n" ); document.write( "in other words
\n" ); document.write( "5y/4=y+1
\n" ); document.write( "5y=4(y+1)
\n" ); document.write( "5y=4y+4
\n" ); document.write( "5y-4y=4
\n" ); document.write( "y=4
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\n" ); document.write( "y=4
\n" ); document.write( "x=y+1=5
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\n" ); document.write( "Then the number is = (10x+y) = 54
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\n" ); document.write( "Hope this helps \n" ); document.write( "

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