document.write( "Question 346714: Find the equation for the line passing through the point (-1,-4) and perpendicular to the line whose equation is 1 x + 3y + 1=0. \n" ); document.write( "
Algebra.Com's Answer #247973 by checkley77(12844)\"\" \"About 
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1 x + 3y + 1=0
\n" ); document.write( "3y=-x-1
\n" ); document.write( "y=-x/3-1/3 (red line). Slope=-1/3
\n" ); document.write( "(-1,-4) and perpendicular.
\n" ); document.write( "The perpendicular line will have a slope=3
\n" ); document.write( "Y=mX+b
\n" ); document.write( "-4=3*-1+b
\n" ); document.write( "-4=-3+b
\n" ); document.write( "b=-4+3
\n" ); document.write( "b=-1 the Y intercept.
\n" ); document.write( "Y=3X-1 answer. (green line)
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-6%2C+5%2C+-6%2C+5%2C+-x%2F3+-1%2F3%2C+3x+-1%29+\" (graph 300x300 pixels, x from -6 to 5, y from -6 to 5, of TWO functions -x/3 -1/3 and 3x -1).
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