document.write( "Question 39302: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #24797 by Paul(988)\"\" \"About 
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First rectangle is 4x, and its width is x
\n" ); document.write( "Second rectangle is 4x+5 in length and x+2 in width
\n" ); document.write( "Area of first is 4x*x=\"4x%5E2\"
\n" ); document.write( "Area of second = \"4x%5E2%2B270\"
\n" ); document.write( "EQUATION:
\n" ); document.write( "\"4x%5E2%2B270=%284x%2B5%29%28x%2B2%29\"
\n" ); document.write( "\"4x%5E2%2B270=4x%5E2%2B13x%2B10\"
\n" ); document.write( "13x=260
\n" ); document.write( "x=20
\n" ); document.write( "4(20)=80
\n" ); document.write( "Hence, the dimensions of the original rectangle are 80cm * 20cm.
\n" ); document.write( "Paul.
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