document.write( "Question 39302: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #24797 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! First rectangle is 4x, and its width is x \n" ); document.write( "Second rectangle is 4x+5 in length and x+2 in width \n" ); document.write( "Area of first is 4x*x= \n" ); document.write( "Area of second = \n" ); document.write( "EQUATION: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "13x=260 \n" ); document.write( "x=20 \n" ); document.write( "4(20)=80 \n" ); document.write( "Hence, the dimensions of the original rectangle are 80cm * 20cm. \n" ); document.write( "Paul. \n" ); document.write( " |