document.write( "Question 346780: Find two consecutive integers such that 2 times the lesser is 19 less than 3 times the greater. \n" ); document.write( "
Algebra.Com's Answer #247959 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "*Note: consecutive integers differ by one and can be represented by:
\n" ); document.write( "n and (n+1)
\n" ); document.write( ".
\n" ); document.write( "The question states the following to be true:
\n" ); document.write( "Write as You read:
\n" ); document.write( "\"2%2An+=+3%2A%28n%2B1%29-19\"
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\n" ); document.write( "Simplify and solve for n.
\n" ); document.write( "\"2%2An+=+3%2An%2B3-19\"
\n" ); document.write( "\"16=+n\"
\n" ); document.write( ".
\n" ); document.write( "The two Integers are 16 and 17
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\n" ); document.write( "Check Your answer:
\n" ); document.write( "32 = 51 - 19\r
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