document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346751>Question 346751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many different arrangements can be formed using the letters P E P P E R </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247957 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6P6 = 6! = 720 = our numerator.\r<BR>\n" );
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document.write( "The denominator will be 2!(3!).  \r<BR>\n" );
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document.write( "Let 2! = the repeated letter E\r<BR>\n" );
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document.write( "Let 3! = the repeated letter P\r<BR>\n" );
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document.write( "6P6 = 720/2!(3!)\r<BR>\n" );
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document.write( "6P6 = 720/(2 x 6)\r<BR>\n" );
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document.write( "6P6 = 720/12\r<BR>\n" );
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document.write( "6P6 = 60\r<BR>\n" );
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