document.write( "Question 346746: If ellen and sue leave school for the library at 3pm. Ellen is going 12 miles per hour n sue is going 9 miles an hour. Ellen gets there 15 mins before sue. What time does ellen get there. How far is the library \n" ); document.write( "
Algebra.Com's Answer #247938 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If ellen and sue leave school for the library at 3pm. \n" ); document.write( " Ellen is going 12 miles per hour n sue is going 9 miles an hour. \n" ); document.write( " Ellen gets there 15 mins before sue. \n" ); document.write( "What time does ellen get there. \n" ); document.write( " How far is the library \n" ); document.write( ": \n" ); document.write( "Change 15 min to .25 hr \n" ); document.write( ": \n" ); document.write( "Let d = distance to the library \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Sue's time - Ellen's time = 15 min \n" ); document.write( " \n" ); document.write( "Multiply both sides by 36, results: \n" ); document.write( "4d - 3d = .25(36) \n" ); document.write( "d = 9 mi is the distance to the library \n" ); document.write( ": \n" ); document.write( "Find Ellen's time to get to the library \n" ); document.write( " \n" ); document.write( "3:00 + :45 = 3:45 time when Ellen get's there \n" ); document.write( " |