document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346756>Question 346756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a group of 5 women and 7 men, how many different committees consisting of 2 women and 3 men can be formed? What if 2 men are feuding and refuse to serve on the committee together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247934 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C(5,2) ways to choose the women<BR>\n" );
document.write( "C(7,3) ways to choose the men<BR>\n" );
document.write( "so C(5,2)*C(7,3)=10*35=350<BR>\n" );
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document.write( "if two men are fighting and do not want to be in the same committe<BR>\n" );
document.write( "C(6,3) basically is like there only 6 men available<BR>\n" );
document.write( "so C(5,2)*C(6,3)=10*20=200 </SPAN>\n" );
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