document.write( "Question 346655: If you save 10$ one month, 12$ the next month, 14$ the next month, and so on, how long will you take to save a total of 400$?
\n" ); document.write( "How would you make this into a formula?
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Algebra.Com's Answer #247925 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
you are looking for summing an arithmetic series
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\n" ); document.write( "the sequence is 10,12,14,..... such that is sum =400
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\n" ); document.write( "\"a%5Bi%5D=a%5B0%5D%2B%28i-1%29%2Adelta\" where \"delta\" is the difference between to consecutive sequence numbers, in this case \"a%5B0%5D=10\" and \"delta=2\"
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\n" ); document.write( "\"a%5Bi%5D=10%2B%28i-1%29%2A2\"=\"8%2B2i\"
\n" ); document.write( "\"sum%28a%5Bi%5D%29\"from 1 to n =\"sum%28%288%2B2i%29%29\"= \"sum%288%29%2B2%2Asum%28i%29\"=\"8n+%2B+2%2A%28n%2A%28n%2B1%29%2F2%29\"=\"8n%2Bn%2A%28n%2B1%29\"=\"8n%2Bn%5E2%2Bn=n%5E2%2B9n\"
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\n" ); document.write( "since we want to know when this sum=400\r
\n" ); document.write( "\n" ); document.write( "\"400=n%5E2%2B9n\"--> \"0=n%5E2%2B9n-400\"
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\n" ); document.write( "solve for n using quadratic formula
\n" ); document.write( "\"+n=%28-9%2B-sqrt%2881-4%2A%28-400%29%29%29%2F2\"
\n" ); document.write( "n=-25 or n=16, since we want the number of months, we take the positive answer
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\n" ); document.write( "\"highlight%28n=16+months%29\"
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