document.write( "Question 39302: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "

Algebra.Com's Answer #24792 by Nate(3500) $\"\"$ $\"About$

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Original:
\n" ); document.write( "length = 4w
\n" ); document.write( "width = w
\n" ); document.write( "Second rectangle:
\n" ); document.write( "length: 5 + 4w
\n" ); document.write( "width = 2 + w
\n" ); document.write( "Equations:
\n" ); document.write( "First triangle: $\"a+%2B+270+=+a\"$
\n" ); document.write( " $\"%284w%29%28w%29+%2B+270+=+%285%2B4w%29%282%2Bw%29\"$
\n" ); document.write( " $\"4w%5E2+%2B+270+=+4w%5E2+%2B+13w+%2B+10\"$
\n" ); document.write( " $\"260+=+13w\"$
\n" ); document.write( " $\"20+=+w\"$
\n" ); document.write( " $\"80+=+l\"$
\n" ); document.write( "Second triangle:
\n" ); document.write( " $\"w+=+22\"$
\n" ); document.write( " $\"l+=+85\"$ \n" ); document.write( "

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