document.write( "Question 346670: Please help me with this Math question:\r
\n" ); document.write( "\n" ); document.write( "sqrt150 - sqrt24 -sqrt54\r
\n" ); document.write( "\n" ); document.write( "Sorry I don't remember how to do the sign for square root on the computer.\r
\n" ); document.write( "\n" ); document.write( "Thank you!!!
\n" ); document.write( "

Algebra.Com's Answer #247879 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
I don't think you are supposed to use a computer or calculator, even if you remember how to use them to find square roots. All computers or calculators can do with most square roots is to find a decimal approximation for the square root.

\n" ); document.write( "Instead, I believe your problem is to simplify the expression. Simplifying square roots involves finding perfect square factors of the radicand, if any. (\"Radicand\" is the name for the expression inside a radical (like a square root).) So we will start by looking for perfect square factors in each of the radicands and, if we find them, rewriting the radicands as a product involving these perfect squares:
\n" ); document.write( "\"sqrt%28150%29+-+sqrt%2824%29+-sqrt%2854%29\"
\n" ); document.write( "\"sqrt%2825%2A6%29+-+sqrt%284%2A6%29+-+sqrt%289%2A6%29\"
\n" ); document.write( "Next we use a property of radicals, \"sqrt%28a%2Ab%29+=+sqrt%28a%29%2Asqrt%28b%29\", to separate the perfect squares factors into their own square roots:
\n" ); document.write( "\"sqrt%2825%29%2Asqrt%286%29+-+sqrt%284%29%2Asqrt%286%29+-+sqrt%289%29%2Asqrt%286%29\"
\n" ); document.write( "Now we can replace the square roots of the perfect squares:
\n" ); document.write( "\"5sqrt%286%29+-+2sqrt%286%29+-+3sqrt%286%29\"
\n" ); document.write( "Now the square roots have been simplified. Next we simplify the expression as a whole, if possible. It turns out that these are like terms so they can be added/subtracted. (If you have trouble seeing this, perhaps using a temporary variable will help. Let \"q+=+sqrt%286%29\". Then the expression becomes: \"5q+-+2q+-3q\". This, I hope you can see, is an expression of like terms. And so is the expression with the square roots of 6!)

\n" ); document.write( "As it turns out, subtracting \"2sqrt%286%29\" from \"5sqrt%286%29\" leaves \"3sqrt%286%29\" (just like 5q - 2q = 3q). And if we then subtract \"3sqrt%286%29\" from \"3sqrt%286%29\" we get 0.

\n" ); document.write( "So the simplified expression is zero!
\n" ); document.write( "
\n" );