document.write( "Question 346579: . A man left A at 6:00 a.m. expecting to reach B at 9:00 a.m. But after walking one hour, he was delayed for half an hour and so he had to increase his rate by 1 mile per hour to reach B at 9:00 a.m. Find his speed before the delay and the distance between A and B.\r
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Algebra.Com's Answer #247878 by ankor@dixie-net.com(22740)\"\" \"About 
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A man left A at 6:00 a.m. expecting to reach B at 9:00 a.m.
\n" ); document.write( " But after walking one hour, he was delayed for half an hour and so he had to
\n" ); document.write( " increase his rate by 1 mile per hour to reach B at 9:00 a.m.
\n" ); document.write( " Find his speed before the delay and the distance between A and B.
\n" ); document.write( ":
\n" ); document.write( "Let d = distance from A to B
\n" ); document.write( "Given that he left at 6, and expected to be there at 9, therefore:
\n" ); document.write( "\"d%2F3\" = original speed
\n" ); document.write( ":
\n" ); document.write( "He walked for 1 hr, then stopped for .5 hrs, therefore
\n" ); document.write( "he continued at a speed of (\"d%2F3\" + 1) for 1.5 hrs
\n" ); document.write( ":
\n" ); document.write( "dist = speed * time
\n" ); document.write( "total dist = slow speed dist + faster speed dist
\n" ); document.write( "d = \"1%28d%2F3%29\" + \"1.5%28d%2F3+%2B+1%29\"
\n" ); document.write( "d = \"d%2F3\" + \"%281.5d%29%2F3+%2B+1.5%29\"
\n" ); document.write( "d = \"%282.5d%29%2F3+%2B+1.5%29\"
\n" ); document.write( "multiply both sides by 3
\n" ); document.write( "3d = 2.5d + 3(1.5)
\n" ); document.write( "3d - 2.5d = 4.5
\n" ); document.write( ".5d = 4.5
\n" ); document.write( "d = \"4.5%2F.5\"
\n" ); document.write( "d = 9 miles from A to B
\n" ); document.write( ":
\n" ); document.write( "Find the original speed:
\n" ); document.write( "\"9%2F3\" = 3 mph
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\n" ); document.write( "Confirm this by finding the distance at each speed
\n" ); document.write( "1 * 3 = 3 miles
\n" ); document.write( "1.5 * 4 = 6 mile
\n" ); document.write( "----------------
\n" ); document.write( "total dist: 9 mi
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