document.write( "Question 346671: The perimeter for a sports field is 292ft.the length is 48ft longer than the width.
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document.write( "what is the width of the field? what is the length of the field? \n" );
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Algebra.Com's Answer #247861 by Alan3354(69443) You can put this solution on YOUR website! Do it like this one: \n" ); document.write( "---------------------- \n" ); document.write( "The length of a rectangle is 10 cm longer than its width. The perimeter of the rectangle is 68 cm. What are the length and width of the rectangle? \n" ); document.write( "------- \n" ); document.write( "Perimeter = 2W + 2L = 68 \n" ); document.write( "W + L = 34 \n" ); document.write( "L = W + 10 \n" ); document.write( "Sub for L in the 1st eqn \n" ); document.write( "W + (W+10) = 34 \n" ); document.write( "2W + 10 = 34 \n" ); document.write( "W = 12 cm \n" ); document.write( " \n" ); document.write( " |