document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346646>Question 346646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a pipe with a circumference of 8 cm and length of 30 cm and that 8 turns of wire are wrapped around the pipe. What is the length of the wire? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247852 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming you mean that the wire makes it turns along the 30 cm length:<BR>\n" );
document.write( "8 times the circumference is the base and the 30 cm is a side of a right triangle.<BR>\n" );
document.write( "The hypotenuse is the length.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L+=+sqrt%2864%5E2+%2B+30%5E2%29+=+sqrt%284996%29 ALIGN=MIDDLE  ALT=\"L+=+sqrt%2864%5E2+%2B+30%5E2%29+=+sqrt%284996%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "L =~ 70.68 cm<BR>\n" );
document.write( " </SPAN>\n" );
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