document.write( "Question 346523: What is the center of the circle x2 + y2 - 2x - 12 = 0? \n" ); document.write( "

Algebra.Com's Answer #247828 by Fombitz(32388) $\"\"$ $\"About$

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Use the caret to denote exponentiation, x^2= $\"x%5E2\"$ .
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\n" ); document.write( "Complete the square in x and y.
\n" ); document.write( " $\"x%5E2+%2B+y%5E2+-+2x+-+12+=+0\"$
\n" ); document.write( " $\"%28x%5E2-2x%29+%2B+%28y-0%29%5E2+-+12+=+0\"$
\n" ); document.write( " $\"%28x%5E2-2x%2B1%29+%2B+%28y-0%29%5E2+-+12+=+1\"$
\n" ); document.write( " $\"%28x-1%29%5E2%2B+%28y-0%29%5E2+=+13\"$
\n" ); document.write( "Compare to the general equation for a circle centered at (h,k) with a radius R:
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"$
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\n" ); document.write( "( $\"h\"$ , $\"k\"$ )=( $\"1\"$ , $\"0\"$ )\r
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