document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346618>Question 346618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Part of $18,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,220 in interest. How much was invested at the lower rate? (Give your answer correct to the nearest cent.) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247819 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Part of $18,000 is invested at 8% annual interest, and the rest is invested at 6%. After one year, the accounts paid $1,220 in interest. How much was invested at the lower rate? (Give your answer correct to the nearest cent.) <BR>\n" );
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document.write( "Let x = amount invested at lower rate of 6%<BR>\n" );
document.write( "then<BR>\n" );
document.write( "18000-x = amount invested at 8%<BR>\n" );
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document.write( "Our equation:<BR>\n" );
document.write( ".06x + .08(18000-x) = 1220<BR>\n" );
document.write( ".06x + 1440 - .08x = 1220<BR>\n" );
document.write( "1440 - .02x = 1220<BR>\n" );
document.write( "-.02x = -220<BR>\n" );
document.write( "x = $11,000.00 </SPAN>\n" );
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