document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346582>Question 346582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I seem to be stuck at this problem.<BR>\n" );
document.write( "I'm not to sure how to write it as the n and n-1 are subscripts.<BR>\n" );
document.write( "Show that an = Sn – Sn-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247770 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S[n]=a[1]+a[2]+a[3]+...+a[n-2]+a[n-1]+[an]<BR>\n" );
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document.write( "S[n-1]=a[1]+a[2]+a[3]+...+a[n-2]+a[n-1]<BR>\n" );
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document.write( "S[n]-S[n-1]=(a[1]-a[1])+(a[2]-a[2])+(a[3]-a[3])+...+(a[n-2]-a[n-2])+(a[n-1]-a[n-1])+a[n]<BR>\n" );
document.write( "S[n]-S[n-1]=(0)+(0)+(0)+...+(0)+(0)+a[n]<BR>\n" );
document.write( "S[n]-S[n-1]=a[n] </SPAN>\n" );
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