document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39334>Question 39334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x and y in the following problem\r<BR>\n" );
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document.write( "18 x +y = 26, 6x -3y = 24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24775 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18X+Y=26 & 6X-3Y=24 MULT EQ #2 BY -3 AND THEN ADD THESE TQO EQ WE GET \r<BR>\n" );
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document.write( "18X+Y=26<BR>\n" );
document.write( "-18X+9Y=-72<BR>\n" );
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document.write( "10Y=-46 Y=-46/10 OR Y=-4.6 THEN 18X-4.6=26 OR 18X=30.6 OR X=30.6/18 OR X=1.7 </SPAN>\n" );
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