document.write( "Question 346433: mike and adam left a bus terminal at the same time and traveled in opposite directions. Mike's bus was in heavy traffic and had to travel 20mi/hr slower than adams's bus. After 3 hours their buses were 270 miles apart. How fast was each bus going \n" ); document.write( "
Algebra.Com's Answer #247717 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let adam's bus speed be x mph \n" ); document.write( "mike's bus speed = x-20 mph \n" ); document.write( ".. \n" ); document.write( "They are going in opposite directions \n" ); document.write( ". \n" ); document.write( "the effective speed = x+x-20 \n" ); document.write( "2x-20 mph. \n" ); document.write( "Time = distance /speed \n" ); document.write( "distance = 270 miles \n" ); document.write( "3= 270/2x-2 \n" ); document.write( "3(2x-2)=270 \n" ); document.write( "6x-6=270 \n" ); document.write( "6x=276 \n" ); document.write( "x=276/6 \n" ); document.write( "x=46 mph adam's bus speed \n" ); document.write( "mike's bus speed = 46-20 =26 mph \n" ); document.write( " |