document.write( "Question 346433: mike and adam left a bus terminal at the same time and traveled in opposite directions. Mike's bus was in heavy traffic and had to travel 20mi/hr slower than adams's bus. After 3 hours their buses were 270 miles apart. How fast was each bus going \n" ); document.write( "
Algebra.Com's Answer #247717 by mananth(16946)\"\" \"About 
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let adam's bus speed be x mph
\n" ); document.write( "mike's bus speed = x-20 mph
\n" ); document.write( "..
\n" ); document.write( "They are going in opposite directions
\n" ); document.write( ".
\n" ); document.write( "the effective speed = x+x-20
\n" ); document.write( "2x-20 mph.
\n" ); document.write( "Time = distance /speed
\n" ); document.write( "distance = 270 miles
\n" ); document.write( "3= 270/2x-2
\n" ); document.write( "3(2x-2)=270
\n" ); document.write( "6x-6=270
\n" ); document.write( "6x=276
\n" ); document.write( "x=276/6
\n" ); document.write( "x=46 mph adam's bus speed
\n" ); document.write( "mike's bus speed = 46-20 =26 mph
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