document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346436>Question 346436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve for x when the area of the rectangle is 30 and the length is 3x+1 and the width is x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247706 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of rectangle = L*W<BR>\n" );
document.write( "30=(3x+1)*x<BR>\n" );
document.write( "30=3x^2+x<BR>\n" );
document.write( "3x^2+x-30=0<BR>\n" );
document.write( "3x^2+10x-9x-90=0<BR>\n" );
document.write( "3x(x+10)-9(x+10)=0<BR>\n" );
document.write( "(x+10)(3x-9)=0<BR>\n" );
document.write( "3(x+10)(x-3)=0<BR>\n" );
document.write( "x=3  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );