document.write( "Question 346160: A) Find the inner product of a and b if a = <4, 5/4, -1/3> and b = < 1/2, -2, -3/2>, and state whether the vector are perpendicular.
\n" ); document.write( "a. 5; no
\n" ); document.write( "b. 5; yes
\n" ); document.write( "c. 0; yes
\n" ); document.write( "d. 0; no\r
\n" ); document.write( "\n" ); document.write( "B) Find the cross product of v and w if v = <-1/3, 4, -3/8> and w = < 6, -4/5, 4>
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Algebra.Com's Answer #247681 by nyc_function(2741)\"\" \"About 
You can put this solution on YOUR website!
Please, post one question at a time. I will answer part (a).\r
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\n" ); document.write( "\n" ); document.write( "Let's compute the inner product, since that will maybe help with deciding which answer to pick.\r
\n" ); document.write( "\n" ); document.write( "a•b = 4(1/2) + (5/4)(-2) + (-1/3)(-3/2)\r
\n" ); document.write( "\n" ); document.write( "= 2 - 5/2 + 3/2\r
\n" ); document.write( "\n" ); document.write( "= 0\r
\n" ); document.write( "\n" ); document.write( "Then that narrows it down to (c) or (d).\r
\n" ); document.write( "\n" ); document.write( "Two vectors are perpendicular when their dot product is the cosine of 90 degrees, which is, as you may recall, 0.\r
\n" ); document.write( "\n" ); document.write( "Then (c) the correct answer.\r
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\n" ); document.write( "\n" ); document.write( "I decided to help you with question (b) as well.\r
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\n" ); document.write( "\n" ); document.write( "Here we have\r
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\n" ); document.write( "\n" ); document.write( "v = -i/3, 4j, -3k/8\r
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\n" ); document.write( "\n" ); document.write( "w = 6i, -4j/5, 4k\r
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\n" ); document.write( "\n" ); document.write( "v x w = (-i/3, 4j, -3k/8) x (6i, -4j/5, 4k)\r
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\n" ); document.write( "\n" ); document.write( "v x w = 0 +4k/5 +4j/3 -24k +0 +16i -18j -12i/40 +0\r
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\n" ); document.write( "\n" ); document.write( "v x w = (16 -12/40).i +(4/3 -18).j +(4/5 -24).k\r
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\n" ); document.write( "\n" ); document.write( "v x w = 15.7(i) -50(j)/3 -116(k)/5 >================< ANSWER\r
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