document.write( "Question 346019: It is desired to draw a triangle so that the first angle is 5/4 of the second but is greater than the third by 40. What should be the magnitudes of the angles of the triangle?\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #247640 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let x = the 1st angle, let y = the 2nd angle, let z = the 3rd angle \n" ); document.write( ": \n" ); document.write( "Write an equation for each phrase \n" ); document.write( "; \n" ); document.write( "\" draw a triangle so that the first angle is 5/4 of the second\" \n" ); document.write( "x = \n" ); document.write( "Multiply both sides by 4 \n" ); document.write( "4x = 5y \n" ); document.write( "divide both sides by 5 \n" ); document.write( " \n" ); document.write( "or we can just write it: \n" ); document.write( "y = .8x \n" ); document.write( ": \n" ); document.write( "\"but is greater than the third by 40.\" \n" ); document.write( "z = x - 40 \n" ); document.write( "; \n" ); document.write( "x + y + z = 180 \n" ); document.write( "Replace y with .8x; replace z with (x-40) \n" ); document.write( "x + .8x + x - 40 = 180 \n" ); document.write( "2.8x = 180 + 40 \n" ); document.write( "x = \n" ); document.write( "x = 78.57 degrees is the 1st angle \n" ); document.write( "and \n" ); document.write( ".8(78.57) = 62.65 degrees is the 2nd angle \n" ); document.write( "and \n" ); document.write( "78.57-40 = 38.57 degrees is the 3rd angle \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "78.57 + 62.65 + 38.57 = 179.79 ~ 180\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |