document.write( "Question 346019: It is desired to draw a triangle so that the first angle is 5/4 of the second but is greater than the third by 40. What should be the magnitudes of the angles of the triangle?\r
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Algebra.Com's Answer #247640 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let x = the 1st angle, let y = the 2nd angle, let z = the 3rd angle
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\n" ); document.write( "Write an equation for each phrase
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\n" ); document.write( "\" draw a triangle so that the first angle is 5/4 of the second\"
\n" ); document.write( "x = \"5%2F4\"y
\n" ); document.write( "Multiply both sides by 4
\n" ); document.write( "4x = 5y
\n" ); document.write( "divide both sides by 5
\n" ); document.write( "\"4%2F5\"x = y
\n" ); document.write( "or we can just write it:
\n" ); document.write( "y = .8x
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\n" ); document.write( "\"but is greater than the third by 40.\"
\n" ); document.write( "z = x - 40
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\n" ); document.write( "x + y + z = 180
\n" ); document.write( "Replace y with .8x; replace z with (x-40)
\n" ); document.write( "x + .8x + x - 40 = 180
\n" ); document.write( "2.8x = 180 + 40
\n" ); document.write( "x = \"220%2F2.8\"
\n" ); document.write( "x = 78.57 degrees is the 1st angle
\n" ); document.write( "and
\n" ); document.write( ".8(78.57) = 62.65 degrees is the 2nd angle
\n" ); document.write( "and
\n" ); document.write( "78.57-40 = 38.57 degrees is the 3rd angle
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\n" ); document.write( "Check solution
\n" ); document.write( "78.57 + 62.65 + 38.57 = 179.79 ~ 180\r
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