document.write( "Question 346245: if a rectangle has an area of 60 in and a perimeter of 38 in, what is the length and width? \n" ); document.write( "

Algebra.Com's Answer #247622 by Fombitz(32388) $\"\"$ $\"About$

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For a rectangle,
\n" ); document.write( "1. $\"A=L%2AW=60\"$
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\n" ); document.write( " $\"P=2L%2B2W=38\"$
\n" ); document.write( "2. $\"L%2BW=19\"$
\n" ); document.write( "From eq. 2,
\n" ); document.write( " $\"L=19-W\"$
\n" ); document.write( "Substitute into eq. 1,
\n" ); document.write( " $\"%2819-W%29W=60\"$
\n" ); document.write( " $\"19W-W%5E2=60\"$
\n" ); document.write( " $\"W%5E2-19W%2B60=0\"$
\n" ); document.write( " $\"%28W-15%29%28W-4%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"W-15=0\"$
\n" ); document.write( " $\"W=15\"$ in
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"L=4\"$ in
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\n" ); document.write( " $\"W-4=0\"$
\n" ); document.write( " $\"W=4\"$ in
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"L=15\"$ in
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\n" ); document.write( "The rectangle measure 4 inches by 15 inches.
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