document.write( "Question 346231: A man rows upstream 16 miles in 4 hours then back downstream in 2 hours. How fast can he row in still water? How fast is the current? \n" ); document.write( "

Algebra.Com's Answer #247585 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!
Hi,
\n" ); document.write( "*Let r be the rate he can row in still water and c be the current.
\n" ); document.write( "r*t =d (rate*time = distance)
\n" ); document.write( ".
\n" ); document.write( "The question states the following to be true:
\n" ); document.write( ".
\n" ); document.write( "(r-c)4hr = 16mi Upstream r = 4 + c
\n" ); document.write( "and
\n" ); document.write( "(r+c)2hr = 16mi Downstream
\n" ); document.write( ".
\n" ); document.write( "Substitute
\n" ); document.write( "((4+c)+ c)*2 = 16
\n" ); document.write( "Solve:
\n" ); document.write( "((4+c)+ c) = 8
\n" ); document.write( "2c + 4 = 8
\n" ); document.write( "2*c = 4
\n" ); document.write( " $\"c+=+highlight%282%28mi%2Fhr%29%29\"$
\n" ); document.write( " $\"r+=highlight%286%28mi%2Fhr%29%29\"$
\n" ); document.write( ".
\n" ); document.write( "Check Your answer:\r
\n" ); document.write( "\n" ); document.write( "(6-2) *4 = 16
\n" ); document.write( "(6+2) *2 = 16 \n" ); document.write( "

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