document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37677>Question 37677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maximizing profit. The total profit (in dollars) for sales of x rowing machines is given by P(x) = 0.2x^2 + 300x - 200. What is the profit if 500 are sold? For what value of x will the profit be at a maximum?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24757 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the profit equation<BR>\n" );
document.write( "P(x) = 0.2x^2 + 300x - 200<BR>\n" );
document.write( "we merely plug in x = 500 and get<BR>\n" );
document.write( "P(500) = .2(500)^2 + 300(500) - 200 = 50000 + 150000 - 200 = $199800<BR>\n" );
document.write( "The x-coordinate of the vertex, and hence of the maximum, is found by -b/2a, but in this case there is no maximum...<BR>\n" );
document.write( "I have a feeling that this P(x) equation is written incorrectly since it has no maximum... </SPAN>\n" );
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