document.write( "Question 346172: What is the probability that a number selected at random from the first 500 positive integers is (exactly) divisible by 6 or 9? \n" ); document.write( "
Algebra.Com's Answer #247541 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! What is the probability that a number selected at random from the first 500 positive integers is (exactly) divisible by 6 or 9?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using as the first 500 positive integers 1 through 500 inclusively\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 83 numbers divisible by 6 exactly between 1 and 500 \n" ); document.write( "(83 * 6 = 498) \n" ); document.write( "there are 55 numbers divisible by 9 exactly between 1 and 500 \n" ); document.write( "(55 * 9 = 495)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of 6: 83/500 = 16.6/100 = 0.166 = 16.6 %\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of 9: 55/500 = 11/100 = 11 %\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of number being divisible by either 6 or 9: (83 + 55)/500 \n" ); document.write( "138/500 = 27.6/100 = 27.6 %\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of number being divisible by either 6 or 9 but not both:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 27 numbers divisible by both 6 and 9 exactly between 1 and 500 \n" ); document.write( "(27 * 18 = 486)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "138 - 27 = 111\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of number being divisible by either 6 or 9 but not both: \n" ); document.write( "111/500 = 22.2/100 = 22.2 % \n" ); document.write( " \n" ); document.write( " |