document.write( "Question 345439: The Transportation Safety Authority (TSA) has developed a new test to detect large amounts of liquid in luggage bags. Based on many test runs, the TSA determines that if a bag does contain large amounts of liquid, there is a probability of 0.92 the test will detect it. If a bag does not contain large amounts of liquid, there is a 0.1 probability the test will conclude that it does (a false positive). Suppose that in reality only 3 in 100 bags actually contain large amounts of liquid. \r
\n" );
document.write( "\n" );
document.write( "A)What is the probability a randomly selected bag will have a positive test? Give your answer to four decimal places.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #247520 by jrfrunner(365) You can put this solution on YOUR website! let D=event of detecting large amount of liquid or positive test \n" ); document.write( "let L=event of bag containing large amounts of liquid \n" ); document.write( "let S=event of bag containing small amounts of liquid \n" ); document.write( "-- \n" ); document.write( "given \n" ); document.write( "P(D/L)=0.92 \n" ); document.write( "P(D/S)=0.1 \n" ); document.write( "P(L)=3/100=0.03 \n" ); document.write( "Need to find P(D) \n" ); document.write( "--- \n" ); document.write( "P(S)=1-P(L)=1-0.03-0.97 \n" ); document.write( "-- \n" ); document.write( "P(D)=P(D and L)+P(D and S) \n" ); document.write( " =P(D/L)*P(L)+P(D/S)*P(S) \n" ); document.write( " =0.92*0.03+0.1*0.97 \n" ); document.write( " =0.0276+0.097=0.1246 \n" ); document.write( " |