document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39293>Question 39293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a. Find the area of a rectangle with sides 2x-7 and x+14<BR>\n" );
document.write( "b. A rectangle has sides (x+9) and (2x+15). Find x if its perimeter is to be 300 units. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24752 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) A = LW = (2x-7)(x+14) = 2x^2 + 28x - 7x - 98 = <BR>\n" );
document.write( "2x^2 + 21x - 98<BR>\n" );
document.write( "b) P = 2L + 2W and so plugging in we get<BR>\n" );
document.write( "P = 300 = 2(x+9) + 2(2x+15)<BR>\n" );
document.write( "300 = 2x + 18 + 4x + 30<BR>\n" );
document.write( "300 = 6x + 48<BR>\n" );
document.write( "6x = 252<BR>\n" );
document.write( "x = 42 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );