document.write( "Question 346140: Write 2x + y = 5 in polar form.\r
\n" ); document.write( "\n" ); document.write( "a. -sqrt 5 = r cos(theta - 27 degree)
\n" ); document.write( "b. sqrt 5 = r cos(theta - 27 degree)
\n" ); document.write( "c. -sqrt 5 = r cos(theta + 27 degree)\
\n" ); document.write( "d. sqrt 5 = r cos(theta + 27 degree)
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Algebra.Com's Answer #247515 by CharlesG2(834)\"\" \"About 
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Write 2x + y = 5 in polar form.\r
\n" ); document.write( "\n" ); document.write( "a. -sqrt 5 = r cos(theta - 27 degree)
\n" ); document.write( "b. sqrt 5 = r cos(theta - 27 degree)
\n" ); document.write( "c. -sqrt 5 = r cos(theta + 27 degree)\
\n" ); document.write( "d. sqrt 5 = r cos(theta + 27 degree)\r
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\n" ); document.write( "\n" ); document.write( "2x + y = 5
\n" ); document.write( "the above is standard form of a linear equation
\n" ); document.write( "in form Ax + By = C, above A = 2, B = 1, and C = 5\r
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\n" ); document.write( "\n" ); document.write( "use x = rcos(theta) and y = rsin(theta), where r^2 = x^2 + y^2 and
\n" ); document.write( "tan(theta) = y/x\r
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\n" ); document.write( "\n" ); document.write( "2(rcos(theta)) + rsin(theta) = 5 (substituted in values)
\n" ); document.write( "2rcos(theta) + rsin(theta) = 5
\n" ); document.write( "r(2cos(theta) + sin(theta)) = 5 (factor out the r)
\n" ); document.write( "r = 5/(2cos(theta) + sin(theta))\r
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\n" ); document.write( "\n" ); document.write( "where you getting those multiple choices?
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