document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=346039>Question 346039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve: One angle of a triangle is 3 times as large as another. The measure of the third angle is 40 degrees more than that of the smallest angle. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #247510 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=247510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is 3 times as large as another. The measure of the third angle is 40 degrees more than that of the smallest angle. Find the measure of each angle. <BR>\n" );
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document.write( "Let x = smallest angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x = largest angle<BR>\n" );
document.write( "x+40 = third angle<BR>\n" );
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document.write( "x + 3x + x+40 = 180<BR>\n" );
document.write( "5x + 40 = 180<BR>\n" );
document.write( "5x = 140<BR>\n" );
document.write( "x = 140/5<BR>\n" );
document.write( "x = 28 degs (smallest)<BR>\n" );
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document.write( "Largest:<BR>\n" );
document.write( "3x = 3(28) = 84 degs<BR>\n" );
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document.write( "Third:<BR>\n" );
document.write( "x+40 = 28+40 = 68 degs<BR>\n" );
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