document.write( "Question 346117: Twice a number decreased by three, and that difference divided by five more than the number. \n" ); document.write( "
Algebra.Com's Answer #247508 by nyc_function(2741)\"\" \"About 
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Let n = the number\r
\n" ); document.write( "\n" ); document.write( "Twice a number decreased by three = 2n - 3.\r
\n" ); document.write( "\n" ); document.write( "...that difference divided by five more than the number = (2n - 3)/(n + 5).\r
\n" ); document.write( "\n" ); document.write( "The entire statement = (2n - 3)/(n + 5).\r
\n" ); document.write( "\n" ); document.write( "What exactly do you need done with this algebraic fraction?\r
\n" ); document.write( "\n" ); document.write( "In other words, where is the rest of the question?\r
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