document.write( "Question 346112: You have $10,000 to invest. Some was invested at 6% and the other at 11% for one year. If you made $800, how much was invested at each percentage? \n" ); document.write( "

Algebra.Com's Answer #247499 by Fombitz(32388) $\"\"$ $\"About$

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Let $\"A\"$ be the amount at 6%, $\"B\"$ the amount at 11%.
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\n" ); document.write( "1. $\"A%2BB=10000\"$
\n" ); document.write( "2. $\"6A%2B11B=80000\"$
\n" ); document.write( "Multiply eq. 1 by (-6) and add to eq. 2,
\n" ); document.write( " $\"-6A-6B%2B6A%2B11B=-60000%2B80000\"$
\n" ); document.write( " $\"5B=20000\"$
\n" ); document.write( " $\"highlight%28+B=4000%29\"$
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"A%2B4000=10000\"$
\n" ); document.write( " $\"highlight%28A=6000%29\"$
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\n" ); document.write( "$6000 at 6% and $4000 at 11%. \n" ); document.write( "

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